We will discuss about the different properties of surds.

If a and b are both rationals and √x and √y are both surds and a + √x = b + √y then a = b and x = y

If a not equal to b, let us assume, b = a + m, where m (m ≠ 0) is a rational.

Now, by question, a + √x = b + √y

⇒ a + √x = a + m + √y

⇒ √x = m + √y, which is impossible (since a simple quadratic surd cannot be equal to the sum of a rational quantity and a simple quadratic surd).

Therefore, we must have, a = b.

When a = b then a + √x = b + √y ⇒ √x = √y ⇒ x = y.

**Notes:**

**1.** If a - √x = b - √y where a, b are both
rationals and √x, √y are both surds, then proceeding as above we can show a = b
and x = y.

**2.** If √x and √y
are actually rationals (in the form of surds), then the relation a + √x = b + √y
does not imply a = b and x = y.

For example, we have,

10 = 6 + 4 = 6 + √16 and 10 = 4 + 6 = 4 + √36

⇒ 6 + √16 = 4 + √36

Evidently we cannot have, 6 = 4 or 16 = 36.

This is due to the fact that √16 and √36 are not surds, they represent rational numbers.

**3.** If a + √x = b
+ √y where a, b are both rationals and √x, √y are both surds then, a = b i.e.
rational parts of two sides are equal and x = y i.e., irrational parts of two
sides are equal.

**4.** If a - √x = b
- √y where a, b are both rationals and √x, √y are both surds then, a = b i.e.
rational parts of two sides are equal and x = y i.e., irrational parts of two
sides are equal.

**5.** If a + √x = 0,
then a = 0 and x = 0.

**6.** If a - √x = 0,
then a = 0 and x = 0.

**7.** If a + √x = b
+ √y then, a - √x = b - √y

**8.** If √(a + √x)
= √b + √y then √(a - √x) = √b - √y

**9.** Identically, if √(a - √x) = √b - √y then √(a
- √x) = √b - √y.

**11 and 12 Grade Math**

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