Lowest Common Multiple of Polynomials
How
to find the lowest common multiple of polynomials?
To find the lowest common multiple (L.C.M.) of
polynomials, we first find the factors of polynomials by the method of
factorization and then adopt the same process of finding L.C.M.
Solved
examples to find lowest common factor of polynomials:
1. Find the L.C.M. of 4a
^{2}  25b
^{2} and 6a
^{2} + 15ab.
Solution:
Factorizing 4a
^{2}  25b
^{2} we get,
(2a)
^{2}  (5b)
^{2}, by using the identity a
^{2}  b
^{2}.
= (2a + 5b) (2a  5b)
Also, factorizing 6a
^{2} + 15ab by taking the common factor '3a', we get
= 3a(2a + 5b)
Therefore, the L.C.M. of 4a
^{2}  25b
^{2} and 6a
^{2} + 15ab is 3a(2a + 5b) (2a  5b)
2. Find the L.C.M. of x
^{2}y
^{2}  x
^{2} and xy
^{2}  2xy  3x.
Solution:
Factorizing x
^{2}y
^{2}  x
^{2} by taking the common factor 'x
^{2}' we get,
x
^{2}(y
^{2}  1)
Now by using the identity a
^{2}  b
^{2}.
x
^{2}(y
^{2}  1
^{2})
= x
^{2}(y + 1) (y  1)
Also, factorizing xy
^{2}  2xy  3x by taking the common factor 'x' we get,
x(y
^{2}  2y  3)
= x(y
^{2}  3y + y  3)
= x[y(y  3) + 1(y  3)]
= x(y  3) (y + 1)
Therefore, the L.C.M. of x
^{2}y
^{2}  x
^{2} and xy
^{2}  2xy  3x is x
^{2}(y + 1) (y  1) (y  3).
3. Find the L.C.M. of x
^{2} + xy, xz + yz and x
^{2} + 2xy + y
^{2}.
Solution:
Factorizing x
^{2} + xy by taking the common factor 'x', we get
x(x + y)
Factorizing xz + yz by taking the common factor 'z', we get
z(x + y)
Factorizing x
^{2} + 2xy + y
^{2} by using the identity (a + b)
^{2}, we get
= (x)
^{2} + 2 (x) (y) + (y)
^{2}
= (x + y)
^{2}
= (x + y) (x + y)
Therefore, the L.C.M. of x
^{2} + xy, xz + yz and x
^{2} + 2xy + y
^{2} is xz(x + y) (x + y).
8th Grade Math Practice
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