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Converse of Pythagoras’ Theorem

If in a triangle the sum of the squares of two sides is equal to the square of the third side then the triangle is a right-angled triangle, the angle between the first two sides being a right angle.

Given In the ∆XYZ, XY2 + YZ2 = XZ2

Converse of Pythagoras’ Theorem Proof

To prove ∠XYZ = 90°

Construction: Draw a ∆PQR in which ∠PQR = 90° and PQ = XY, QR = YZ

Proof:

In the right-angled ∆PQR, PR2 = PQ2 + QR2

Therefore, PR2 = XY2 + YZ2 = XZ2

Therefore, PR = XZ

Now, in ∆XYZ and ∆PQR, XY = PQ, YZ = QR and XZ = PR

Therefore, ∆XYZ ≅ ∆PQR (by SSS criterion of congruency)

Therefore, ∠XYZ = ∠PQR = 90° (CPCTC)


Problems on Converse of Pythagoras’ Theorem

1. If the sides of a triangle are in the ratio 13:12:5, prove that the triangle is a right-angled triangle. Also state which angle is the right angle.

Solution:

Let the triangle be PQR.

Converse of Pythagoras’ Theorem

Here the sides are PQ = 13k, QR = 12k and RP = 5k

Now, QR2 + RP2 = (12k)2 + (5k)2

                                           = 144k2 + 25k2

                                           = 169k2

                                           = (13k)2

                                           = PQ2

Therefore, by converse of Pythagoras theorem, PQR is a right-angled triangle in which ∠R = 90°.





9th Grade Math

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