Equality of Complex Numbers

We will discuss about the equality of complex numbers.

Two complex numbers z1 = a + ib and z2 = x + iy are equal if and only if a = x and b = y i.e., Re (z1) = Re (z2) and Im (z1) = Im (z2).

Thus, z1 = z2 ⇔ Re (z1) = Re (z2) and Im (z1) = Im (z2).

For example, if the complex numbers z1 = x + iy and z2 = -5 + 7i are equal, then x = -5 and y = 7.


Solved examples on equality of two complex numbers:

1. If z1 = 5 + 2yi and z2 = -x + 6i are equal, find the value of x and y.

Solution:

The given two complex numbers are z1 = 5 + 2yi and z2 = -x + 6i.

We know that, two complex numbers z1 = a + ib and z2 = x + iy are equal if a = x and b = y.

z1 = z2

β‡’ 5 + 2yi = -x + 6i

β‡’ 5 = -x and 2y = 6

β‡’ x = -5 and y = 3

Therefore, the value of x = -5 and the value of y = 3.

 

2. If a, b are real numbers and 7a + i(3a - b) = 14 - 6i, then find the values of a and b.

Solution:

Given, 7a + i(3a - b) = 14 - 6i

β‡’ 7a + i(3a - b) = 14 + i(-6)

Now equating real and imaginary parts on both sides, we have

7a = 14 and 3a - b = -6

β‡’ a = 2 and 3 βˆ™ 2 – b = -6

β‡’ a = 2 and 6 – b = -6

β‡’ a = 2 and – b = -12

β‡’ a = 2 and b = 12

Therefore, the value of a = 2 and the value of b = 12.

 

3. For what real values of m and n are the complex numbers m2 – 7m + 9ni and n2i + 20i -12 are equal.

Solution:

Given complex numbers are m2 - 7m + 9ni and n2i + 20i -12

According to the problem,

m2 - 7m + 9ni = n2i + 20i -12

β‡’ (m2 - 7m) + i(9n) = (-12) + i(n2 + 20)

Now equating real and imaginary parts on both sides, we have

m2 - 7m = - 12 and 9n = n2 + 20

β‡’ m2 - 7m + 12 = 0 and n2 - 9n + 20 = 0

β‡’ (m - 4)(m - 3) = 0 and (n - 5)(n - 4) = 0

β‡’ m = 4, 3 and n = 5, 4

Hence, the required values of m and n are follows:

m = 4, n = 5; m = 4, n = 4; m = 3, n = 5; m = 3, n = 4.




11 and 12 Grade Math 

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