# Subtracting 2-digit Numbers with Borrowing

Here we will learn subtracting 2-digit numbers with borrowing. The subtractions with borrowing are solved step-by-step in four different ways.

Worked-out examples on subtracting 2-digit numbers with borrowing:

1. Subtract 9 from 15.

Solution:

T        O

1        5

-          9

Since, 5 < 9, so 9 cannot be subtracted from 5. So, 1 ten, i.e., 10 ones is borrowed from the digit 1 of tens place. Now one ten, i.e., 10 ones are added to 5 ones to make it 15 ones. Now 15 ones – 9 ones = 6 ones.

Therefore, 15 – 9 = 6

2. Subtract 37 from 65

Solution:

The numbers are placed in column form, with the smaller number 37 written under the greater number 65.

T        O

1 T   →  10

6        5

-   3        7

2       8

(i) first ones are subtracted as 5 < 7 or 7 > 5. So, 7 cannot be subtracted from 5.

(ii) Now 1 ten is borrowed from 6 tens leaving 5 tens there.

(iii) 1 ten = 10 ones. So, 10 ones are added to 5 ones making the sum 15 ones

(iv) 7 ones are subtracted from 15 ones i.e., 15 ones – 7 ones = 8 ones. This 8 is written in one’s column.

(v) Now tens are subtracted. At ten’s place there are 5 tens left. So 5 tens – 3 tens = 2 tens. So, 2 is written in ten’s column.

(vi) Therefore, 65 – 37 = 28.

3. Subtract 28 from 83

Solution:

The smaller number 28 is written under greater number 83 in column form and ones are subtracted first, then the tens.

T        O

1 T  →   10

8        3

-   2        8

5       5

(i) 3 < 8, so 1 ten, i.e., 10 ones are borrowed from 8 tens with 7tens remaining there.

(ii) Now, 1 ten + 3 = 10 + 3 = 13 ones. So, 13 ones – 8 ones = 5 ones.

(iii) 7 tens – 2 tens = 5 tens.

Therefore, 83 – 28 = 55

4. Subtract 69 from 92

Solution:

The smaller number 69 is written under greater number 92 in column form and ones are subtracted first, then the tens.

T        O

1 T  →   10

9        2

-   6        9

2       3

(i)  10 + 2 = 12; 12 O – 9 O = 3 O

(ii) 8 T – 6 T = 2 T

Therefore, 92 – 69 = 23