# Subtracting 2-digit Numbers with Borrowing (Regrouping)

Here we will learn subtracting 2-digit numbers with borrowing. The subtractions with borrowing are solved step-by-step in four different ways.

When we need to subtract bigger number from a smaller number in ones place, we regroup tens into ones.

Regrouping

We can write a 2-digit number in different ways by regrouping tens and ones.

16 can be written as

23 can be written as

Let us understand this with the help of an example.

A shopkeeper sells bananas. He has 6 bunches of 10's and 5 single bananas.

Nairitee wants to buy 37 bananas from the shopkeeper. The shopkeeper gives her 3 bunches of 10's and breaks one bunch of 10's to give 7 bananas.

The shopkeeper is now left with how many bananas?

Column Method

Arrange the numbers in columns and subtract. In ones place, 5 is smaller than 7. We cannot take away 7 from 5. So, we break one ten into 10 ones. Now we have, 15 ones in ones place and 5 tens in tens place.

 15 ones - 7 ones = 8We write 8 in ones place.Subtract 3 tens from 5 tens.5 tens - 3 tens = 2 tensWrite 2 in tens place.

So, 65 - 37 = 28

Worked-out examples on subtracting 2-digit numbers with borrowing:

1. Subtract 9 from 15.

Solution:

T        O

1        5

-          9

Since, 5 < 9, so 9 cannot be subtracted from 5. So, 1 ten, i.e., 10 ones is borrowed from the digit 1 of tens place. Now one ten, i.e., 10 ones are added to 5 ones to make it 15 ones. Now 15 ones – 9 ones = 6 ones.

Therefore, 15 – 9 = 6

2. Subtract 37 from 65

Solution:

The numbers are placed in column form, with the smaller number 37 written under the greater number 65.

T        O

1 T   →  10

6        5

-   3        7

2       8

(i) first ones are subtracted as 5 < 7 or 7 > 5. So, 7 cannot be subtracted from 5.

(ii) Now 1 ten is borrowed from 6 tens leaving 5 tens there.

(iii) 1 ten = 10 ones. So, 10 ones are added to 5 ones making the sum 15 ones

(iv) 7 ones are subtracted from 15 ones i.e., 15 ones – 7 ones = 8 ones. This 8 is written in one’s column.

(v) Now tens are subtracted. At ten’s place there are 5 tens left. So 5 tens – 3 tens = 2 tens. So, 2 is written in ten’s column.

(vi) Therefore, 65 – 37 = 28.

3. Subtract 28 from 83

Solution:

The smaller number 28 is written under greater number 83 in column form and ones are subtracted first, then the tens.

T        O

1 T  →   10

8        3

-   2        8

5       5

(i) 3 < 8, so 1 ten, i.e., 10 ones are borrowed from 8 tens with 7tens remaining there.

(ii) Now, 1 ten + 3 = 10 + 3 = 13 ones. So, 13 ones – 8 ones = 5 ones.

(iii) 7 tens – 2 tens = 5 tens.

Therefore, 83 – 28 = 55

4. Subtract 69 from 92

Solution:

The smaller number 69 is written under greater number 92 in column form and ones are subtracted first, then the tens.

T        O

1 T  →   10

9        2

-   6        9

2       3

(i)  10 + 2 = 12; 12 O – 9 O = 3 O

(ii) 8 T – 6 T = 2 T

Therefore, 92 – 69 = 23

Subtraction with Borrowing:

5. Let us subtract 5 from 23.

 Step I: Arrange the numbers into tens and ones. Step II: We cannot subtract 5 from 3.So, borrow 1 ten from the tens column.1 ten = 10 ones.Take these 10 ones to the ones column.This gives: 10 + 3 = 13 ones13 – 5 = 8 Step III: Subtract the tens.Now since we borrowed 1 ten, we are left with 1 ten in the tens column.

Thus, 23 – 5 = 18

6. Let us subtract 37 from 53.

 Step I: Arrange the numbers into tens and ones. Step II: We cannot subtract 7 from 3.So, borrow 1 ten from the tens column.1 ten = 10 ones.Take these 10 ones to the ones column.This gives: 10 + 3 = 13 ones13 – 7 = 6 Step III: Since we have borrowed 1 ten from 5 tens, we are left with 4 tens. Now subtract 3 tens from 4 tens.4 – 3 = 1

Thus, 53 – 37 = 16

Questions and Answers on Subtracting 2-Digit Numbers with Borrowing (Regrouping):

1. Regrouping the tens and ones.

 (i) 24 = 2 tens + 4 ones = 1 ten + 14 ones
 (ii) 57 = ___ tens + ___ ones = 4 tens + ___ ones
 (iii) 64 = ___ tens + ___ ones = ___ tens + 14 ones
 (iv) 48 = ___ tens + ___ ones = 3 tens + ___ ones

2. Subtracting 1-digit number from 2-digit number with regrouping.

(i) 38 - 9 = _____

(ii) 62 - 7 = _____

(iii) 44 - 6 = _____

(iv) 67 - 8 = _____

(v) 75 - 7 = _____

(vi) 94 - 8 = _____

(vii) 74 - 5 = _____

(viii) 51 - 2 = _____

(ix) 95 - 6 = _____

(x) 42 - 3 = _____

(xi) 53 - 4 = _____

(xii) 62 - 4 = _____

(xiii) 67 - 8 = _____

(xiv) 32 - 5 = _____

(xv) 22 - 9 = _____

(xvi) 93 - 3 = _____

2. (i) 29

(ii) 55

(iii) 38

(iv) 59

(v) 68

(vi) 86

(vii) 69

(viii) 49

(ix) 89

(x) 39

(xi) 49

(xii) 58

(xiii) 59

(xiv) 27

(xv) 13

(xvi) 90

3. Subtracting 2-digit number with regrouping.

(i) 80 - 17 = _____

(ii) 38 - 29 = _____

(iii) 71 - 34 = _____

(iv) 47 - 19 = _____

(v) 86 - 27 = _____

(vi) 65 - 47 = _____

(vii) 51 - 25 = _____

(viii) 62 - 37 = _____

(ix) 73 - 57 = _____

(x) 94 - 46 = _____

(xi) 46 - 28 = _____

(xii) 56 - 27 = _____

(xiii) 57 - 19 = _____

(xiv) 31 - 24 = _____

(xv) 41 - 16 = _____

(xvi) 53 - 29 = _____

3. (i) 63

(ii) 9

(iii) 37

(iv) 28

(v) 59

(vi) 18

(vii) 26

(viii) 25

(ix) 16

(x) 48

(xi) 18

(xii) 29

(xiii) 38

(xiv) 7

(xv) 25

(xvi) 24

4. Subtract.

 (i) - T          O   6          3   4          6__________ (ii) - T          O   3          4   2          9__________
 (iii) - T          O   9          3   5          8__________ (iv) - T          O   7          6   5          9__________
 (v) - T          O   3          2   1          5__________ (vi) - T          O   4          4   3          6__________
 (vii) - T          O   5          2   2          8__________ (viii) - T          O   3          2   1          9__________
 (ix) - T          O   8          3   6          9__________ (x) - T          O   7          5   2          6__________

4. (i) 17

(ii) 5

(iii) 35

(iv) 17

(v) 17

(vi) 8

(vii) 24

(viii) 13

(ix) 14

(x) 49

## You might like these

• ### Language of Addition | Total | Altogether | Plus | Add | Sum | In all

What are the languages of addition? The language of addition are total, total number, more than, altogether, together, plus, double, make, all, in all, add, increase, increased by, sum, and.

In 2nd grade math practice you will get all types of examples on different topics along with the solutions. Second grade math games are arranged in such a way that students can learn math

In 2nd grade practice worksheet 1 we will solve the problems on place value, expended form, ascending order, descending order, addition facts, subtraction fact, multiplication fact, division, division using reverse multiplication and different types of word problems.

• ### Division using Reverse Multiplication | Multiplication Table | Divide

We will learn how to do division using reverse multiplication.

• ### Divide on a Number Line | Various Division Problems | Solved Examples

How to divide on a number line? Learn to divide using number line to find the quotient. Solved examples to show divide on a number line: 1. Solve 14 ÷ 7 Solution: 7 is subtracted repeatedly

• ### Basic Division Facts | Division is the Inverse of Multiplication |Math

Some basic division facts are needed to follow for dividing numbers. The repeated subtraction of the same number is expressed by division in short form and in long form.

• ### Problem Solving on Multiplication | Multiplication Statement Problems

Problem solving on multiplication will help us to get the idea on how to solve the basic multiplication statement problems. 1. Three groups of ponies are eating. There are 2 ponies in each group.

• ### Find the Product using Multiplication Property | Product of any Number

How to find the product using multiplication property? 1. Order property When two numbers are multiplied we get a product. When the places of numbers are interchanged, their product remains the same

• ### Basic Multiplication Facts | Repeated Addition |Multiplication Process

Some basic multiplication facts are needed to follow for multiplying numbers. The repeated addition of the same number is expressed by multiplication in short.

• ### Multiplying 1-Digit Number | Multiplication of One-Digit Numbers

We know the process of multiplying 1-digit number by another 1-digit number. The multiplication of one-digit numbers is done with the help of the multiplication table of the number concerned.