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Quadratic Equation has Only Two Roots

We will discuss that a quadratic equation has only two roots or in other words we can say that a quadratic equation cannot have more than two roots.

We will prove this one-by-one.


A quadratic equation has only two roots.

Proof:

Let us, consider the quadratic equation of the general form

ax2 + bx + c = 0, (a ≠ 0) ............... (i)

Now divide each term by a (since, a ≠ 0), we get

x2 + bax + ca = 0

⇒ x2 + 2 * x * b2a + (b2a)2 – (b2a)2 + ca = 0

⇒ (x + b2a)2 - b24ac4a2 = 0

⇒ (x + b2a)2(b24ac2a)2 = 0

⇒ (x + b2a + b24ac2a)(x + b2a - b24ac2a) = 0

⇒ [x - (bb24ac2a)][x - (b+b24ac2a)] = 0

⇒ (x - α)(x - β) = 0, where α = bb24ac2a and β = b+b24ac2a

Now we can clearly see that the equation ax2 + bx + c = 0 reduces to (x - α)(x - β) = 0 and the equation ax2 + bx + c = 0 is only satisfied by the values x = α and x = β.

Except α and β no other values of x satisfies the equation ax2 + bx + c = 0.

Hence, we can say that the equation ax2 + bx + c = 0 has two and only two roots.

Therefore, a quadratic equation has two and only two roots.


Solved example on quadratic equation:

Solve the quadratic equation x2 - 4x + 13 = 0

Solution:

The given quadratic equation is x2 - 4x + 13 = 0

Comparing the given equation with the general form of the quadratic equation ax2 + bx  + c = 0, we get

a = 1, b = -4 and c = 13

Therefore, x = b±b24ac2a

⇒ x = (4)±(4)24(1)(13)2(1)

⇒ x = 4±16522

⇒ x = 4±362

⇒ x = 4±6i2, [Since i = √-1]

⇒ x = 2 ± 3i

Hence, the given quadratic equation has two and only two roots.

The roots are 2 + 3i and 2 - 3i.





11 and 12 Grade Math 

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