Here we will prove that of all the straight lines that can be drawn to a straight line from a given point outside it, the perpendicular is the shortest.
Given: XY is a straight line and O is a point outside it. OP is perpendicular to XY and OZ is an oblique.
To Prove: OP < OZ.
Proof:
Statement 
Reason 
1. In ∆OPZ, ∠OPZ = 90°. 
1. OP ⊥ XY. 
2. ∠OZP is an acute angle. 
2. In a triangle, if one angle is a right angle, the other two must be acute. 
3. ∠OZP < ∠OPZ. 
3. From statement 1 and 2. 
4. OP < OZ. (proved) 
4. In a triangle, the greater angle has the greater side opposite to it. 
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