Here we will learn how to solve the application problems on lateral surface area of a cuboid using the formula.

Formula for finding the lateral surface area of a cuboid

Area of a Rooms is example of cuboids.

Are of the four walls of a room = sum of the four vertical (or lateral) faces

= 2(l + b)h

Where l = Length, b = breadth and h = height.

Therefore, **lateral surface area of a cuboid = 2(l +
b)h**

Problems on Lateral Surface Area of a Cuboid:

The dimensions of a cubical room are 8.6 m × 5.4 m × 4 m.
The room has two doors each measuring 2 m by 1 m and four windows each
measuring 1 m by 1 m. What will be the cost of plastering the four walls and
the ceiling at RS 65 per m^{2}?

**Solution:**

The total area of the four walls

= Lateral surface area of the cuboid

= 2(l + b)h

=
2(86 + 5.4) × 4 m^{2}

=
112 m^{2}.

The area of the ceiling = l × b

=
8.6 × 5.4 m^{2}

= 46.44 m^{2}

The sum of the areas of the two doors and the four windows

=
2(2 × 1) m^{2} + 4(1 × 1) m^{2}

=
8 m^{2}

Therefore, the total area to be plastered = (112 + 46.44 -
8) m^{2}

=
150.44 m^{2}

Therefore, the cost of plastering = 150.44 × Rs. 65

= Rs. 9778.60.

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