A solid with uniform cross section perpendicular to its length (or height) is a cylinder. The cross section may be a circle, a triangle, a square, a rectangle or a polygon. A can, a pencil, a book, a glass prism, etc., are examples of cylinders. Each one of the figures shown below is a cylinder.

The second figure shown above is a cuboid, which is also a cylinder. The cylinder depicted in the last figure is also called prism.

The formule for the volume and the surface area of a cylinder are the same as those of solids with uniform cross section.

Volume of a Cylinder = (Area of the cross section) × length (or height or breadth)

= A × h

Lateral surface area of a Cylinder = (Perimeter of the cross section) × length (or height or breadth)

= P × h

Total surface area of a Cylinder = Lateral surface area + Sum of the areas of the two plane ends

= P × h + 2 × A

Solved Problems on Volume and Surface Area of Cylinder:

1. The cross section of a cylinder is a trapezium whose parallel sides measure 10 cm and 6 cm, and the distance between the parallel sides is 8 cm. If the cylinder is 20 cm long, find (i) the area of the cross section; and (ii) the volume of the cylinder.


Volume and Surface Area of Cylinder

(i) The area of the cross section = area of the trapezium

                                               = \(\frac{1}{2}\) (10 + 6)8 cm2

                                               = 64 cm2

(ii) The volume of the cylinder = (Area of the cross Section) × length

                                            = 64 cm2 × 20 cm

                                            = 1280 cm3

2. The cross section of a cylinder is a regular hexagon of side 4 cm and its height measures 12 cm. Find its (i) lateral surface area, and (ii) total surface area.


Regular Hexagon Cylinder

(i) The perimeter of the cross section

                                   = Perimeter of a regulator hexagon of side 4 cm

                                   = 6 × 4 cm

                                   = 24 cm.

Therefore, lateral surface area of the cylinder

                                   = (Perimeter of the cross section) × height

                                   = 24 cm × 12 cm

                                   = 288 cm2

(ii) Total surface area = lateral surface area + 2 × (Area of the Cross Section)

               = 288 cm2 + 2 × (Area of the regular hexagon of side 4 cm)

               = 288 cm2 + 2 × \(\frac{3√3}{2}\) × 4^2 cm2

               = (288 + 48√3) cm2

               = (288 + 83.04) cm2

                = 371.04 cm2

9th Grade Math

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