Quadratic Equation has Only Two Roots

We will discuss that a quadratic equation has only two roots or in other words we can say that a quadratic equation cannot have more than two roots.

We will prove this one-by-one.


A quadratic equation has only two roots.

Proof:

Let us, consider the quadratic equation of the general form

ax2 + bx + c = 0, (a β‰  0) ............... (i)

Now divide each term by a (since, a β‰  0), we get

x2 + bax + ca = 0

β‡’ x2 + 2 * x * b2a + (b2a)2 – (b2a)2 + ca = 0

β‡’ (x + b2a)2 - b2βˆ’4ac4a2 = 0

β‡’ (x + b2a)2 – (√b2βˆ’4ac2a)2 = 0

β‡’ (x + b2a + √b2βˆ’4ac2a)(x + b2a - √b2βˆ’4ac2a) = 0

β‡’ [x - (βˆ’bβˆ’βˆšb2βˆ’4ac2a)][x - (βˆ’b+√b2βˆ’4ac2a)] = 0

β‡’ (x - Ξ±)(x - Ξ²) = 0, where Ξ± = βˆ’bβˆ’βˆšb2βˆ’4ac2a and Ξ² = βˆ’b+√b2βˆ’4ac2a

Now we can clearly see that the equation ax2 + bx + c = 0 reduces to (x - Ξ±)(x - Ξ²) = 0 and the equation ax2 + bx + c = 0 is only satisfied by the values x = Ξ± and x = Ξ².

Except Ξ± and Ξ² no other values of x satisfies the equation ax2 + bx + c = 0.

Hence, we can say that the equation ax2 + bx + c = 0 has two and only two roots.

Therefore, a quadratic equation has two and only two roots.


Solved example on quadratic equation:

Solve the quadratic equation x2 - 4x + 13 = 0

Solution:

The given quadratic equation is x2 - 4x + 13 = 0

Comparing the given equation with the general form of the quadratic equation ax2 + bx  + c = 0, we get

a = 1, b = -4 and c = 13

Therefore, x = βˆ’b±√b2βˆ’4ac2a

β‡’ x = βˆ’(βˆ’4)±√(βˆ’4)2βˆ’4(1)(13)2(1)

β‡’ x = 4±√16βˆ’522

β‡’ x = 4Β±βˆšβˆ’362

β‡’ x = 4Β±6i2, [Since i = √-1]

β‡’ x = 2 Β± 3i

Hence, the given quadratic equation has two and only two roots.

The roots are 2 + 3i and 2 - 3i.





11 and 12 Grade Math 

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