# Slope of the Graph of y = mx + c

Here we will learn how to solve the slope of the graph of y = mx + c.

The graph of y = mx + c is a straight line joining the points (0, c) and ($$\frac{-c}{m}$$, 0).

Let M = ($$\frac{-c}{m}$$, 0) and N = (0, c) and ∠NMX = θ.

Then, tan θ is called the slope of the line which is the graph of y = mx + c.

Now, ON = c and OM = $$\frac{c}{m}$$.

Therefore, in the right-angled ∆MON, tan θ = $$\frac{ON}{OM}$$ = $$\frac{c}{\frac{c}{m} }$$ = m.

Thus, the slope of the line which is the graph of y = mx + c is m

And m is equal to the tangent of the angle that the line makes with the positive direction of the x-axis.

Solved examples on slope of the graph of y = mx + c:

1. What is the slope of the line which makes 60° with the positive direction of the x-axis?

Solution:

The slope = tan 60° = √3

2. What is the slope of the line which is the graph of 2x – 3y + 5 = 0?

Solution:

Here, 2x – 3y + 5 = 0

⟹ 3y = 2x + 5

⟹ y = $$\frac{2}{3}$$x + $$\frac{5}{3}$$.

Comparing with y = mx + c, we have m = $$\frac{2}{3}$$.

Therefore, the slope of the line is $$\frac{2}{3}$$.

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