We will discuss here how to solve step-by-step the long division method with regrouping and with remainder.
Consider the following examples:
1. 527 ÷ 3
Step I: Begin with hundreds digit 5 hundreds ÷ 3 = 1 hundred
with remainder 2 hundreds Step II: Bring down 2 tens to the right of 2 hundreds 2 hundreds + 2 tens = 22 tens Step III: 22 tens ÷ 3 = 7 tens with remainder 1 ten Step IV: Bring down 7 ones to the right of 1 ten. Then, 1 ten + 7 ones = 17 ones Step V: 17 ones ÷ 3 = 5 ones with remainder 2 ones. |
Therefore, 527 ÷ 3 = 175 with remainder 2
2. 6311 ÷ 4
Step I: Begin with thousands digit 6 thousands ÷ 4 = 1 thousand with remainder 2 thousands
Step II: Bring down 3 hundreds to the right of 2 thousands. Then, 2 thousands + 3 hundreds = 23 hundreds Step III: Now 23 hundreds ÷ 4 = 5 hundreds with remainder 3 hundreds Step IV: Bring down 1 ten to the right of 3 hundreds Then, 3 hundreds + 1 ten = 31 tens Step V: Now, 31 tens ÷ 4 = 7 tens with remainder 3 tens Step VI: Bring down 1 one to the right of 3 tens then 3 tens + 1 one = 31 ones Now 31 ones ÷ 4 = 7 ones with remainder 3 ones |
Therefore 6311 ÷ 4 = 1577 with remainder 3
From Long Division Method with Regrouping and with Remainder to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
May 19, 24 06:35 PM
May 19, 24 03:36 PM
May 19, 24 03:19 PM
May 19, 24 02:23 PM
May 19, 24 01:26 PM
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.