# Long Division Method with Regrouping and with Remainder

We will discuss here how to solve step-by-step the long division method with regrouping and with remainder.

Consider the following examples:

1. 527 ÷ 3 Step I: Begin with hundreds digit 5 hundreds ÷ 3 = 1 hundred with remainder 2 hundreds Step II: Bring down 2 tens to the right of 2 hundreds 2 hundreds + 2 tens = 22 tens Step III: 22 tens ÷ 3 = 7 tens with remainder 1 ten Step IV: Bring down 7 ones to the right of 1 ten. Then, 1 ten + 7 ones = 17 ones Step V: 17 ones ÷ 3 = 5 ones with remainder 2 ones.

Therefore, 527 ÷ 3 = 175 with remainder 2

2. 6311 ÷ 4 Step I: Begin with thousands digit 6 thousands ÷ 4 = 1 thousand with remainder 2 thousands Step II: Bring down 3 hundreds to the right of 2 thousands. Then, 2 thousands + 3 hundreds = 23 hundreds Step III: Now 23 hundreds ÷ 4 = 5 hundreds with remainder 3 hundreds Step IV: Bring down 1 ten to the right of 3 hundreds Then, 3 hundreds + 1 ten = 31 tens Step V: Now, 31 tens ÷ 4 = 7 tens with remainder 3 tens Step VI: Bring down 1 one to the right of 3 tens then 3 tens + 1 one = 31 ones Now 31 ones ÷ 4 = 7 ones with remainder 3 ones

Therefore 6311 ÷ 4 = 1577 with remainder 3

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