We will learn how to prove the property of the inverse trigonometric function arcsec(x) + arccsc(x) = \(\frac{π}{2}\) (i.e., sec\(^{-1}\) x + csc\(^{-1}\) x = \(\frac{π}{2}\)).
Proof: Let, sec\(^{-1}\) x = θ
Therefore, x = sec θ
x = csc (\(\frac{π}{2}\) - θ), [Since, csc (\(\frac{π}{2}\) - θ) = sec θ]
⇒ csc\(^{-1}\) x = \(\frac{π}{2}\) - θ
⇒ csc\(^{-1}\) x= \(\frac{π}{2}\) - sec\(^{-1}\) x, [Since, θ = sec\(^{-1}\) x]
⇒ csc\(^{-1}\) x + sec\(^{-1}\) x = \(\frac{π}{2}\)
⇒ sec\(^{-1}\) x + csc\(^{-1}\) x = \(\frac{π}{2}\)
Therefore, sec\(^{-1}\) x + csc\(^{-1}\) x = \(\frac{π}{2}\). Proved.
11 and 12 Grade Math
From arcsec x + arccsc x = π/2 to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.
Dec 13, 24 08:43 AM
Dec 13, 24 12:31 AM
Dec 12, 24 11:22 PM
Dec 12, 24 10:31 PM
Dec 09, 24 10:39 PM
New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.