In 5th Grade BODMAS Rule Worksheet you will get different types of problems on mathematical expressions involving different operations, mathematical expression with 'brackets' and 'of' and simplifying mathematical expressions in a certain order of operations.
I. Simplify the following mathematical expressions using BODMAS or PEMDAS rule:
1. 6\(\frac{2}{5}\) × \(\frac{1}{15}\) + \(\frac{1}{5}\) ÷ \(\frac{2}{5}\) - \(\frac{1}{15}\)
2. 2\(\frac{1}{2}\) ÷ 3\(\frac{7}{18}\) + \(\frac{1}{6}\) - \(\frac{1}{9}\) × 18 + 1\(\frac{1}{6}\)
3. 2\(\frac{3}{7}\) ÷ \(\frac{4}{7}\) + 2\(\frac{1}{2}\) - \(\frac{1}{2}\) × \(\frac{1}{7}\)
4. 2\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\) ÷ \(\frac{3}{8}\) - 2\(\frac{1}{3}\) × 1\(\frac{1}{7}\)
5. 1\(\frac{1}{9}\) ÷ \(\frac{5}{18}\) + \(\frac{2}{5}\) × \(\frac{5}{9}\) - \(\frac{1}{9}\)
6. 3 + 3\(\frac{3}{10}\) ÷ \(\frac{3}{5}\) + 2\(\frac{1}{5}\) × \(\frac{2}{11}\)
7. 5\(\frac{2}{5}\) ÷ 2 + 2\(\frac{1}{5}\) - 1\(\frac{3}{5}\) × \(\frac{5}{8}\)
8. 2\(\frac{1}{2}\) ÷ \(\frac{3}{10}\) + \(\frac{4}{5}\) × \(\frac{15}{32}\) - \(\frac{1}{9}\)
II. Fill in the correct symbol (+, -, x, ÷).
1. 24 ⟎ 8 + 6 = 9
2. 20 ÷ 5 ⟎ 3=1
3. 16 + 16 ⟎ 4 ÷ 2 = 48
4. 8 + 7 - 40 ⟎ 5 = 7
5. 4\(\frac{1}{2}\) ⟎ 3\(\frac{1}{2}\) - 4 ÷ 2 = 6
6. \(\frac{3}{10}\) ⟎ \(\frac{2}{10}\) + \(\frac{3}{2}\) = 2
III. Simplify the following order of operations using BODMAS rule:
1. (2\(\frac{1}{4}\) + 3\(\frac{2}{5}\)) ÷ (1\(\frac{1}{3}\) + 1\(\frac{1}{6}\)) × 2\(\frac{1}{4}\)
2. 15 ÷ [2\(\frac{1}{2}\) + {2 (2 + \(\overline{1\frac{1}{3} - \frac{1}{2}}\))}]
3. 2\(\frac{1}{2}\) + {4 (5 + \(\overline{6 - 4}\))}
4. 12 + [4 - {1 + (4 × \(\frac{3}{8}\))}]
5. 2\(\frac{1}{2}\) [9\(\frac{1}{2}\) - (19\(\frac{1}{2}\) - \(\overline{7\frac{1}{5} × 1\frac{1}{2}}\))}
6. 8\(\frac{7}{8}\) - (1\(\frac{1}{5}\) - \(\overline{\frac{1}{2} - \frac{1}{4}}\)) of 8
7. 9 + [\(\frac{1}{2}\) of {6 - 2 (9 - \(\overline{6 - 3}\))}]
8. \(\frac{1}{7}\) of [5 + {3 (9 + \(\overline{3 - 2}\))}] - 3
9. 24 + [4 - {3 + (6 × \(\frac{1}{18}\))}] ÷ \(\frac{2}{3}\)
10. (14\(\frac{1}{4}\) - 1\(\frac{3}{5}\)) × (\(\frac{1}{16}\) of 3\(\frac{1}{5}\)) ÷ 1\(\frac{4}{9}\)
11. (2\(\frac{3}{4}\) - \(\frac{1}{4}\)) ÷ 1\(\frac{4}{9}\) - (\(\frac{1}{3}\) × \(\frac{3}{8}\)) ÷ \(\frac{1}{8}\) + 2
12. (21\(\frac{1}{7}\) - 2\(\frac{2}{9}\)) × (\(\frac{4}{9}\) of 4 × \(\frac{3}{8}\)) ÷ 1\(\frac{1}{9}\)
I. 1. \(\frac{43}{50}\)
2. \(\frac{13}{183}\)
3. 6\(\frac{19}{28}\)
4. 2\(\frac{2}{9}\)
5. 4\(\frac{1}{9}\)
6. 8\(\frac{9}{10}\)
7. 3\(\frac{9}{10}\)
8. 8\(\frac{43}{72}\)
II. 1. ÷
2. -
3. ×
4. ÷
5. +
6. +
III. 1. 5\(\frac{17}{200}\)
2. 1\(\frac{41}{49}\)
3. 30\(\frac{1}{2}\)
4. 13\(\frac{1}{2}\)
5. 2
6. 1\(\frac{11}{40}\)
7. 12
8. 2
9. 25
10. 1\(\frac{977}{1300}\)
11. 2\(\frac{19}{26}\)
12. 11\(\frac{37}{105}\)
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