5th Grade BODMAS Rule Worksheet

In 5th Grade BODMAS Rule Worksheet you will get different types of problems on mathematical expressions involving different operations, mathematical expression with 'brackets' and 'of' and simplifying mathematical expressions in a certain order of operations. 

I. Simplify the following mathematical expressions using BODMAS or PEMDAS rule:

1. 6\(\frac{2}{5}\) × \(\frac{1}{15}\) + \(\frac{1}{5}\)  ÷ \(\frac{2}{5}\) - \(\frac{1}{15}\)

2. 2\(\frac{1}{2}\) ÷ 3\(\frac{7}{18}\) + \(\frac{1}{6}\) - \(\frac{1}{9}\) × 18 + 1\(\frac{1}{6}\)

3. 2\(\frac{3}{7}\) ÷ \(\frac{4}{7}\) + 2\(\frac{1}{2}\) - \(\frac{1}{2}\) × \(\frac{1}{7}\)

4. 2\(\frac{3}{4}\) ÷ 1\(\frac{1}{2}\) ÷ \(\frac{3}{8}\) - 2\(\frac{1}{3}\) × 1\(\frac{1}{7}\)

5. 1\(\frac{1}{9}\) ÷ \(\frac{5}{18}\) + \(\frac{2}{5}\) × \(\frac{5}{9}\) - \(\frac{1}{9}\)

6. 3 + 3\(\frac{3}{10}\) ÷ \(\frac{3}{5}\) + 2\(\frac{1}{5}\) × \(\frac{2}{11}\)

7. 5\(\frac{2}{5}\) ÷ 2 + 2\(\frac{1}{5}\) - 1\(\frac{3}{5}\) × \(\frac{5}{8}\)

8. 2\(\frac{1}{2}\) ÷ \(\frac{3}{10}\) + \(\frac{4}{5}\) × \(\frac{15}{32}\) - \(\frac{1}{9}\)

II. Fill in the correct symbol (+, -, x, ÷).

1. 24 ⟎ 8 + 6 = 9

2. 20 ÷ 5 ⟎ 3=1

3. 16 + 16 ⟎ 4 ÷ 2 = 48

4. 8 + 7 - 40 ⟎ 5 = 7

5. 4\(\frac{1}{2}\) ⟎ 3\(\frac{1}{2}\) - 4 ÷ 2 = 6

6. \(\frac{3}{10}\) ⟎ \(\frac{2}{10}\) + \(\frac{3}{2}\) = 2

III. Simplify the following order of operations using BODMAS rule:

1. (2\(\frac{1}{4}\) + 3\(\frac{2}{5}\)) ÷ (1\(\frac{1}{3}\) + 1\(\frac{1}{6}\)) × 2\(\frac{1}{4}\)

2. 15 ÷ [2\(\frac{1}{2}\) + {2 (2 + \(\overline{1\frac{1}{3} - \frac{1}{2}}\))}]

3. 2\(\frac{1}{2}\) + {4 (5 + \(\overline{6 - 4}\))}

4. 12 + [4 - {1 + (4 × \(\frac{3}{8}\))}]

5. 2\(\frac{1}{2}\) [9\(\frac{1}{2}\) - (19\(\frac{1}{2}\) - \(\overline{7\frac{1}{5} × 1\frac{1}{2}}\))}

6. 8\(\frac{7}{8}\) - (1\(\frac{1}{5}\) - \(\overline{\frac{1}{2} - \frac{1}{4}}\)) of 8

7. 9 + [\(\frac{1}{2}\) of {6 - 2 (9 - \(\overline{6 - 3}\))}]

8. \(\frac{1}{7}\) of [5 + {3 (9 + \(\overline{3 - 2}\))}] - 3

9. 24 + [4 - {3 + (6 × \(\frac{1}{18}\))}] ÷ \(\frac{2}{3}\)

10. (14\(\frac{1}{4}\) - 1\(\frac{3}{5}\)) × (\(\frac{1}{16}\) of 3\(\frac{1}{5}\)) ÷ 1\(\frac{4}{9}\)

11. (2\(\frac{3}{4}\) - \(\frac{1}{4}\)) ÷ 1\(\frac{4}{9}\) - (\(\frac{1}{3}\) × \(\frac{3}{8}\)) ÷ \(\frac{1}{8}\) + 2

12. (21\(\frac{1}{7}\) - 2\(\frac{2}{9}\)) × (\(\frac{4}{9}\) of 4 × \(\frac{3}{8}\)) ÷ 1\(\frac{1}{9}\)

5th Grade BODMAS Rule Worksheet Answer

I. 1. \(\frac{43}{50}\)

2. \(\frac{13}{183}\)

3. 6\(\frac{19}{28}\)

4. 2\(\frac{2}{9}\)

5. 4\(\frac{1}{9}\)

6. 8\(\frac{9}{10}\)

7. 3\(\frac{9}{10}\)

8. 8\(\frac{43}{72}\)

II. 1. ÷

2. -

3. ×

4. ÷

5. +

6. +

III. 1. 5\(\frac{17}{200}\)

2. 1\(\frac{41}{49}\)

3. 30\(\frac{1}{2}\)

4. 13\(\frac{1}{2}\)

5. 2

6. 1\(\frac{11}{40}\)

7. 12

8. 2

9. 25

10. 1\(\frac{977}{1300}\)

11. 2\(\frac{19}{26}\)

12. 11\(\frac{37}{105}\)

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