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Long Division Method with Regrouping and without Remainder
We will discuss here how to solve step-by-step the long division method with regrouping and without remainder.
Consider the following examples:
A. Dividing a 2-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
Division by Regrouping 2-digit Numbers
1. Divide 92 by 4.
Solution:
Step I: Arrange the numbers in columns.
Divide 9 tens by 4.
4 × 2 = 8, 8 < 9
and 4 × 3 = 12, 12 > 9
So, 9 - 8 = 1
We have 1 ten left.
Step II:
Bring down 2 ones.
We now have 1 ten and 2 ones = 12 ones as the new dividend.
On reciting the table of 4,
we get 4 × 3 = 12
So, the quotient is 23.
B. Dividing a 3-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
Division by Regrouping 3-digit Numbers
1. 468 ÷ 3
Let us follow the division along with the given steps.
 |
Step I: Begin with hundreds digit 4 hundreds ÷ 3 = 1 hundred with remainder 1 hundred
Step II: Bring down 6 tens to the right of 1 hundred 1 hundred + 6 tens = 16 tens Step III: 16 tens ÷ 3 = 5 tens with remainder 1 ten Step IV: Bring down 8 ones to the right of 1 ten 1 ten + 8 ones = 18 ones Step V: 18 ones ÷ 3 = 6 ones |
Therefore, 468 ÷ 3 = 156
2. Divide 675 by 3.
Solution:
Step I: Divide the 6 hundreds. (3 × 2 = 6)
Subtract the hundreds: 6 - 6 = 0
Step II: Divide the 7 tens. (3 × 2 = 6)
Subtract the tens: 7 - 6 = 1,
i.e., 1 ten is left.
So, bring down 5 ones.
Step III: Now, we have 10 ones (1 ten) + 5 ones = 15 ones.
Divide 15 ones by 3. (3 × 5 = 15)
Subtract the ones:
15 - 15 = 0
Therefore, Quotient = 225, Remainder = 0.
C. Dividing a 4-Digits Number by 1-Digit Number With Regrouping and Without Remainder:
1. 9120 ÷ 5
Let us follow the division along with the given steps.
 |
Step I: Begin with thousands digit 9 thousands ÷ 5 = 1 thousand with remainder 4 thousands
Step II: Bring down 1 hundred to the right of 4 thousands Step III: Now 4 thousands + 1 hundred = 41 hundreds Step IV: Now 41 hundreds ÷ 5 = 8 hundreds with remainder 1 hundred Step V: Bring down 2 tens to the right of 1 hundred Step VI: Now 1 hundred + 2 tens = 12 tens Step VII: So, 12 tens ÷ 5 = 2 with remainder 2 tens Step VIII: Bring down zero to the right of 2 tens So, 2 tens + 0 ones = 20 ones Now 20 ones ÷ 5 = 4 ones |
Therefore, 9120 ÷ 5 = 1824
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