Math Blog
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Newly added pages can be seen from this page. Keep visiting to this page so that you will remain updated.en-usMathThu, 21 Mar 2019 15:31:45 -0400Thu, 21 Mar 2019 15:31:45 -0400math-only-math.comMar 21, Criteria of Similarity between Triangles | SAS Criterion of Similarity
https://www.math-only-math.com/criteria-of-similarity-between-triangles.html8c551ef3e60f5f98e617fca38d3324a2We will discuss here about the different criteria of similarity between triangles with the figures. 1. SAS criterion of similarity: If two triangles have an angle of one equal to an angle of the other and the sides including them are proportional, the triangles are similar.Thu, 21 Mar 2019 15:31:42 -0400Mar 20, Similar Triangles | Congruency and Similarity of Triangles | Diagram
https://www.math-only-math.com/similar-triangles.htmla29be216e23486f3417f2bbef150ce45We will discuss here about the similar triangles. If two triangles are similar then their corresponding angles are equal and corresponding sides are proportional. Here, the two triangles XYZ and PQR are similar. So, ∠X = ∠P, ∠Y = ∠Q, ∠Z = ∠R and XY/PQ=YZ/QR = XZ/PR. ∆XYZ isWed, 20 Mar 2019 17:12:05 -0400Mar 19, Properties of size Transformation |Enlargement|Reduction|Scale Factor
https://www.math-only-math.com/properties-of-size-transformation.html0bca71df3ee8efef5966a47299f28fc3We will discuss here about the different properties of size transformation. 1. The shape of the image is the same as that of the object. 2. If the scale factor of the transformation is k then each side of the image is k times the corresponding side of the object.Tue, 19 Mar 2019 17:34:08 -0400Mar 17, Reduction Transformation | Centre of Reduction | Reduction Factor
https://www.math-only-math.com/reduction-transformation.html9c470d8444d45d52bd33eebbcfe8af21We will discuss here about the similarity on Reduction transformation. In the figure given below ∆X’Y’Z’ is a reduced image of ∆XYZ. The two triangles are similar. Here also the triangles are equiangular and \(\frac{X’Y’}{XY}\) = \(\frac{Y’Z’}{YZ}\) = \(\frac{Z’X’}{ZX}\) = kSun, 17 Mar 2019 17:37:43 -0400Mar 17, Enlargement Transformation | Centre of Enlargement |Enlargement Factor
https://www.math-only-math.com/enlargement-transformation.html22bbdeeda296be67ffeea261500f354eWe will discuss here about the similarity on enlargement transformation. Cut out some geometrical figures like triangles, quadrilaterals, etc., from a piece of cardboard. Hold these figures, one-by-one, between a point source of light and a wall. Sun, 17 Mar 2019 15:36:59 -0400Mar 8, Proof By the Equal Intercepts Theorem | Line Joining the Midpoints
https://www.math-only-math.com/proof-by-the-equal-intercepts-theorem.htmld172495b241c6f0cccf15a9650a83b50Here we will prove that in the given ∆XYZ, M and N are the midpoints of XY and XZ respectively. T is any point on the base YZ. Prove that MN bisects XT. Solution: Given: In ∆XYZ, XM = MY and XN = NZ. MN cuts XT at U. To prove: XU = UT. Construction: Through X, draw PQ ∥ YZ.Fri, 8 Mar 2019 16:10:23 -0500Mar 8, Midpoint Theorem by using the Equal Intercepts Theorem |Proof |Diagram
https://www.math-only-math.com/midpoint-theorem-by-using-the-equal-intercepts-theorem.html1ca75e3e796b8fcd37827022f6c20921Here we will prove that converse of the Midpoint Theorem by using the Equal Intercepts Theorem. Solution: Given: P is the midpoint of XY in ∆XYZ. PQ ∥ YZ. To prove: XQ = QZ. Construction: Through X, draw MN ∥ YZ. Proof: Statement 1. PQ ∥ YZ. 2. MN ∥ PQ ∥ YZ.Fri, 8 Mar 2019 14:48:00 -0500Mar 5, Problems on Equal Intercepts Theorem | Midpoint Theorem | Diagram
https://www.math-only-math.com/problems-on-equal-intercepts-theorem.html3cf41d8dd2bee0bd1512e467332a738bHere we will solve different types of problems on Equal Intercepts Theorem. 1. In the given figure, MN ∥ KL ∥ GH and PQ = QR. If ST = 2.2 cm, find SU. Solution: The transversal PR makes equal intercepts, PQ and QR, on the three parallel lines MN, KL and GH. Therefore, by theTue, 5 Mar 2019 18:24:33 -0500Feb 26, Equal Intercepts Theorem | Transversal makes Equal Intercepts
https://www.math-only-math.com/equal-intercepts-theorem.html35643909306d36b35563a2e4240fd236Intercept In the figure given above, XY is a transversal cutting the line L1 and L2 at P and Q respectively. The line segment PQ is called the intercept made on the transversal XY by the lines L1 and L2. If a transversal makes equal intercepts on three or more parallel linesTue, 26 Feb 2019 14:36:59 -0500Feb 25, Collinear Points Proved by Midpoint Theorem | Collinearity | Diagram
https://www.math-only-math.com/collinear-points-proved-by-midpoint-theorem.htmla7112a3501587e6b991cf82a092a86c6In ∆XYZ, the medians ZM and YN are produced to P and Q respectively such that ZM = MP and YN = NQ. Prove that the points P, X and Q are collinear, and X is the midpoint of PQ. Solution: Given: In ∆XYZ, the points M and N are the midpoints of XY and XZ respectively.Mon, 25 Feb 2019 14:45:16 -0500Feb 22, Midpoint Theorem on Right-angled Triangle | Proof | Statement | Reason
https://www.math-only-math.com/midpoint-theorem-on-right-angled-triangle.html454cf9f12bd6d66471b7dc8e7d075837Here we will prove that in a right-angled triangle the median drawn to the hypotenuse is half the hypotenuse in length. Solution: In ∆PQR, ∠Q = 90°. QD is the median drawn to hypotenuse PRFri, 22 Feb 2019 14:28:35 -0500Feb 21, Midsegment Theorem on Trapezium | Nonparallel Sides of a Trapezium
https://www.math-only-math.com/midsegment-theorem-on-trapezium.htmlea1ba5508578c7d93b1cb0a56fd2d579Here we will prove that the line segment joining the midpoints of the nonparallel sides of a trapezium is half the sum of the lengths of the parallel sides and is also parallel to them. Solution: Given: PQRS is a trapezium in which PQ ∥ RS. U and V are theThu, 21 Feb 2019 11:55:27 -0500Feb 20, Midpoint Theorem on Trapezium | Converse of the Midpoint Theorem
https://www.math-only-math.com/midpoint-theorem-on-trapezium.html2ed1b4ed31c52c1aaaa9259688806f1fPQRS is a trapezium in which PQ ∥ RS. T is the midpoint of QR. TU is drawn parallel to PQ which meets PS at U. Prove that 2TU = PQ + RS. Given: PQRS is a trapezium in which PQ ∥ RS. T is the midpoint of QR. TU ∥ PQ and TU meets PS at U. To prove: 2TU = PQ + RS. ConstructionWed, 20 Feb 2019 14:10:14 -0500Feb 13, Straight Line Drawn from the Vertex of a Triangle to the Base |Diagram
https://www.math-only-math.com/straight-line-drawn-from-the-vertex-of-a-triangle-to-the-base.html5a7bd7ddca3ce151ea2158526d799c57Here we will prove that any straight line drawn from the vertex of a triangle to the base is bisected by the straight line which joins the middle points of the other two sides of the triangle. Solution: Given: Q and R are the midpoints of the sides XY and XZ respectively ofWed, 13 Feb 2019 16:56:46 -0500Feb 12, Four Triangles which are Congruent to One Another | Prove with Diagram
https://www.math-only-math.com/four-triangles-which-are-congruent-to-one-another.htmlb78f37ceb8c9ddf73c2a89707d1a7ce3Here we will show that the three line segments which join the middle points of the sides of a triangle, divide it into four triangles which are congruent to one another. Solution: Given: In ∆PQR, L, M and N are the midpoints of QR, RP and PQ respectively. To prove ∆PMN ≅ LNMTue, 12 Feb 2019 14:48:34 -0500Feb 11, Midpoint Theorem Problem | Midpoint Theorem | Converse of Midpoint
https://www.math-only-math.com/midpoint-theorem-problem.html48e0fed8d299d2b83419230864cda284Here we will learn how to solve different types of midpoint theorem problem. In the adjoining figure, find (i) ∠QPR, (ii) PQ if ST = 2.1 cm. Solution: In ∆PQR, S and T are the midpoints of PR and QR respectively. Therefore, ST = \(\frac{1}{2}\)PQ and ST ∥ PQ.Mon, 11 Feb 2019 16:57:42 -0500Feb 6, Converse of Midpoint Theorem | Proof of Converse of Midpoint Theorem
https://www.math-only-math.com/converse-of-midpoint-theorem.htmlc4783fcbf0bd33cb2983cc47b1b0d1e8The straight line drawn through the midpoint of one side of a triangle parallel to another bisects the third side. Given: In ∆PQR, S is the midpoint of PQ, and ST is drawn parallel to QR. To prove: ST bisects PR, i.e., PT = TR. Construction: Join SU where U is the midpointWed, 6 Feb 2019 15:35:00 -0500Feb 4, Midpoint Theorem |AAS & SAS Criterion of Congruency Prove with Diagram
https://www.math-only-math.com/midpoint-theorem.htmledc5bae19b5ff24210dbdd2c7d00d6e8The line segment joining the midpoints of two sides of a triangle is parallel to the third side and equal to half of it. Given: A triangle PQR in which S and T are the midpoint of PQ and PR respectively. To prove: ST ∥ QR and ST = 1/2QR Construction: Draw RU ∥ QP such that Mon, 4 Feb 2019 18:03:57 -0500Jan 31, Sum of Four Sides of a Quadrilateral Exceeds the Sum of the Diagonals
https://www.math-only-math.com/sum-of-the-four-sides-of-a-quadrilateral-exceeds-the-sum-of-the-diagonals.htmlab7054bd88cc2b38c503998ba8d039acHere we will prove that in any quadrilateral the sum of the four sides exceeds the sum of the diagonals. Solution: Given: ABCD is a quadrilateral; AC and BD are its diagonals. To prove: (AB + BC + CD + DA) > (AC + BD). Proof: Statement 1. In ∆ADB, (DA + AB) > BD.Thu, 31 Jan 2019 17:33:31 -0500Jan 30, Sum Of Any Two Sides Is Greater Than Twice The Median | Proof|Diagram
https://www.math-only-math.com/sum-of-any-two-sides-is-greater-than-twice-the-median.html8c474089523850f86387527ada70bad6Here we will prove that in a triangle the sum of any two sides is greater than twice the median which bisects the remaining side. Solution: Given: In ∆XYZ, XP is the median that bisects YZ at P. To prove: (XY + XZ) > 2XP. Construction: Produce XP to Q such that XP = PQ.Wed, 30 Jan 2019 15:25:30 -0500Jan 28, Problem on Inequalities in Triangle | Solution with Diagram
https://www.math-only-math.com/problem-on-inequalities-in-triangle.html2ba41d9f39f1759a5ba55682521e4305Here we will solve the problem on inequalities in triangle. Let XYZ be a triangle in which XM bisects ∠YXZ. Prove that XY is greater than YM. As XM bisects ∠YXZ, we have ∠YXZ = ∠MXZ ............ (i) Also, in ∆XMZ, ∠XMY > ∠MXZ, as an exterior angle of a triangle is alwaysMon, 28 Jan 2019 17:37:40 -0500Jan 25, Comparison of Sides and Angles in a Triangle | Geometrical Property
https://www.math-only-math.com/comparison-of-sides-and-angles-in-a-triangle.htmla5df1799899b1fcf68cf77f97336c682Here we will solve different types of problems on comparison of sides and angles in a triangle. 1. In ∆XYZ, ∠XYZ = 35° and ∠YXZ = 63°. Arrange the sides of the triangle in the descending order of their lengths. ∠XZY = 180° - (∠XYZ + ∠YXZ) = 180° - (35° + 63°) = 180° - 98°Fri, 25 Jan 2019 17:50:07 -0500Jan 24, Perpendicular is the Shortest Theorem | Inequalities in Triangle
https://www.math-only-math.com/perpendicular-is-the-shortest.html04126b0e87197ea134955f432f1feca6Here we will prove that of all the straight lines that can be drawn to a straight line from a given point outside it, the perpendicular is the shortest. Given: XY is a straight line and O is a point outside it. OP is perpendicular to XY and OZ is an oblique. To Prove: OP <OZThu, 24 Jan 2019 15:11:09 -0500Jan 23, The Sum of any Two Sides of a Triangle is Greater than the Third Side
https://www.math-only-math.com/the-sum-of-any-two-sides-of-a-triangle-is-greater-than-the-third-side.html7c11a4bcf72d7939569a7c78e8511b3eHere we will prove that the sum of any two sides of a triangle is greater than the third side. Given: XYZ is a triangle. To Prove: (XY + XZ) > YZ, (YZ + XZ) > XY and (XY + YZ) > XZ Construction: Produce YX to P such that XP = XZ. Join P and Z. Statement 1. ∠XZP = ∠XPZ.Wed, 23 Jan 2019 16:56:18 -0500Jan 21, Greater Side has the Greater Angle Opposite to It | Triangle Inequalit
https://www.math-only-math.com/greater-side-has-the-greater-angle-opposite-to-it.html81bcaa3a346e3e0ca6e8e4e045b58794Here we will prove that if two sides of a triangle are unequal, the greater side has the greater angle opposite to it. Given: In ∆XYZ, XZ > XY To prove: ∠XYZ > ∠XZY. Construction: From XZ, cut off XP such that XP equals XY. Join Y and P. Proof: Statement 1. In ∆XYP, ∠XYP =Mon, 21 Jan 2019 17:34:10 -0500Jan 21, Greater Angle has the Greater Side Opposite to It | Prove with Diagram
https://www.math-only-math.com/greater-angle-has-the-greater-side-opposite-to-it.htmlc9bb7e32e300815e6fbd026b2668d358Here we will prove that if two angles of a triangle are unequal, the greater angle has the greater side opposite to it. Given: In ∆XYZ, ∠XYZ > ∠XZY To Prove: XZ > XY Proof: Statement 1. Let us assume that XZ is not greater than XY. Then XZ must be either equal to or lessMon, 21 Jan 2019 17:31:49 -0500Jan 17, Theorem on Isosceles Triangle | Proof Involving Isosceles Triangles
https://www.math-only-math.com/theorem-on-isosceles-triangle.html961080ef6cd77c9951d89cf6d26eaf08Here we will prove that the equal sides YX and ZX of an isosceles triangle XYZ are produced beyond the vertex X to the points P and Q such that XP is equal to XQ. QY and PZ are joined. Show that QY is equal to PZ. Solution: In ∆XYZ, XY = XZ. YX and XZ are produced to P andThu, 17 Jan 2019 14:31:59 -0500Jan 16, Points on the Base of an Isosceles Triangle | Prove with Diagram
https://www.math-only-math.com/base-of-an-isosceles-triangle.htmlda0f6a7391b900b99823c2596e958c8eHere we will prove that if two given points on the base of an isosceles triangle are equidistant from the extremities of the base, show that they are also equidistance from the vertex. Solution: Given: In the isosceles ∆XYZ, XY = XZ, M and N points on the base YZ such thatWed, 16 Jan 2019 14:29:49 -0500Jan 15, Lines Joining the Extremities of the Base of an Isosceles Triangle
https://www.math-only-math.com/straight-lines-joining-the-extremities-of-the-base-of-an-isosceles-triangle.html90841070873238102c830d64747bf4d8Here we will show that the straight lines joining the extremities of the base of an isosceles triangle to the midpoints of the opposite sides are equal. Solution: Given: In ∆XYZ, XY = XZ, M and N are the midpoints of XY and XZ respectively.Tue, 15 Jan 2019 16:56:51 -0500Jan 10, Problem on Two Isosceles Triangles on the Same Base | Proof | Diagram
https://www.math-only-math.com/problem-on-two-isosceles-triangles-on-the-same-base.html25fce0483d3d3ae7bb12c1b608c46db8Here we will prove that ∆PQR and ∆SQR are two isosceles triangles drawn on the same base QR and on the same side of it. If P and S be joined, prove that each of the angles ∠QPR and ∠QSR will be divided by the line PS into two equal parts.Thu, 10 Jan 2019 16:36:07 -0500Jan 9, Problems on Properties of Isosceles Triangles | Find x° and y°
https://www.math-only-math.com/problems-on-properties-of-isosceles-triangles.html75bbd1c3208f5102ffcfaa27ddec6a6dHere we will solve some numerical problems on the properties of isosceles triangles Find x° from the given figures. In ∆XYZ, XY = XZ. Therefore, ∠XYZ = ∠XZY = x°. Now, ∠YXZ + ∠XYZ + XZY = 180° ⟹ 84° + x° + x° = 180° ⟹ 2x° = 180° - 84° ⟹ 2x° = 96°Wed, 9 Jan 2019 17:34:31 -0500Jan 7, Three Angles of an Equilateral Triangle are Equal | Axis of Symmetry
https://www.math-only-math.com/three-angles-of-an-equilateral-triangle.html2e421cde09b3209f6da124228ce7a00fHere we will prove that if the three angles of a triangle are equal, it is an equilateral triangle. Given: In ∆XYZ, ∠YXZ = ∠XYZ = ∠XZY. To prove: XY = YZ = ZX. Proof: Statement 1. XY = ZX. 2. XY = YZ. 3. XY = YZ = ZX. (Proved) Reason 1. Sides opposite to equal angles ∠XZYMon, 7 Jan 2019 13:13:36 -0500Jan 5, Sides Opposite to the Equal Angles of a Triangle are Equal | Diagram
https://www.math-only-math.com/sides-opposite-to-the-equal-angles-of-a-triangle-are-equal.html1eb193fbbb41ede3607c33cc6cc025d4Here we will prove that the sides opposite to the equal angles of a triangle are equal. Given: In ∆ABC, ∠XYZ = ∠XZY. To prove: XY = XZ. Construction: Draw the bisector XM of ∠YXZ so that it meets YZ at M. Proof: Statement 1. In ∆XYM and ∆XZM, (i) ∠XYM = XZM (ii) ∠YXM = ∠ZXMSat, 5 Jan 2019 15:16:59 -0500Jan 3, The Three Angles of an Equilateral Triangle are Equal | With Diagram
https://www.math-only-math.com/the-three-angles-of-an-equilateral-triangle-are-equal.html83aa43b02c0d02be891e3a333d04daa7Here we will prove that the three angles of an equilateral triangle are equal. Given: PQR is an equilateral triangle. To prove: ∠QPR = ∠PQR = ∠ PRQ. Proof: Statement 1. ∠QPR = ∠PQR 2. ∠PQR = ∠ PRQ. 3. ∠QPR = ∠PQR = ∠ PRQ. (Proved). Reason 1. Angles opposite to equal sides QRThu, 3 Jan 2019 17:19:18 -0500Jan 2, Equal Sides of an Isosceles Triangle are Produced, the Exterior Angles
https://www.math-only-math.com/equal-sides-of-an-isosceles-triangle.htmla3c095c9319d6d02b9d55a1d504b1b1aHere we will prove if the equal sides of an isosceles triangle are produced, the exterior angles are equal. Given: In the isosceles triangle PQR, the equal sides PQ and PR are produced to S and T respectively. To prove: ∠RQS = ∠QRT. Proof: Statement 1. ∠PQR = ∠PRQ 2. ∠RQSWed, 2 Jan 2019 14:23:00 -0500Jan 1, Angles Opposite to Equal Sides of an Isosceles Triangle are Equal
https://www.math-only-math.com/angles-opposite-to-equal-sides-of-an-isosceles-triangle-are-equal.htmld8f4149932935093a97f036d8997d0e8Here we will prove that in an isosceles triangle, the angles opposite to the equal sides are equal. Solution: Given: In the isosceles ∆XYZ, XY = XZ. To prove ∠XYZ = ∠XZY. Construction: Draw a line XM such that it bisects ∠YXZ and meets the side YZ at M. Proof: StatementTue, 1 Jan 2019 16:41:15 -0500Dec 31, Application of Congruency of Triangles | Isosceles triangle Proved
https://www.math-only-math.com/application-of-congruency-of-triangles.htmle3caaa91c392d548571f78342909ef46Here we will prove some Application of congruency of triangles. PQRS is a rectangle and POQ an equilateral triangle. Prove that SRO is an isosceles triangle. Solution: Given: PQRS is a rectangle. POQ is an equilateral triangle to prove ∆SOR is an isosceles triangle. Proof:Mon, 31 Dec 2018 15:47:37 -0500Dec 28, Prove that the Bisectors of the Angles of a Triangle Meet at a Point
https://www.math-only-math.com/bisectors-of-the-angles-of-a-triangle-meet-at-a-point.html2850dc977aeb1d1e1cbf8fd4225a33dbHere we will prove that the bisectors of the angles of a triangle meet at a point. Solution: Given In ∆XYZ, XO and YO bisect ∠YXZ and ∠XYZ respectively. To prove: OZ bisects ∠XZY. Construction: Draw OA ⊥ YZ, OB ⊥ XZ and OC ⊥ XY. Proof: Statement 1. In ∆XOC and ∆XOBFri, 28 Dec 2018 17:45:43 -0500Dec 27, Point on the Bisector of an Angle | Corresponding Parts of a Triangles
https://www.math-only-math.com/point-on-the-bisector-of-an-angle.html3c7d75335af6158ef3c26b7858d4c5ceHere we will prove that any point on the bisector of an angle is equidistant from the arms of that angle. Solution: Given OZ bisects ∠XOY and PM ⊥ XO and PN ⊥ OY. To prove PM = PN. Proof: Statement 1. In ∆OPM and ∆OPN, (i) ∠MOP = ∠NOP. (ii) ∠OMP = ∠ONP = 90°Thu, 27 Dec 2018 17:08:14 -0500Dec 27, Prove that an Altitude of an Equilateral Triangle is also a Median
https://www.math-only-math.com/altitude-of-an-equilateral-triangle-is-also-a-median.html7708820dac7a8a46ae1c2a722167fdfeHere we will prove that an altitude of an equilateral triangle is also a median. In a ∆PQR, PQ = PR. Prove that the altitude PS is also a medina. Solution: Given in ∆PQR, PQ = PR and PS ⊥ QR.To prove PS is a median, i.e., QS = SR Proof: Statement 1. In ∆PQS and ∆PRS,Thu, 27 Dec 2018 17:07:08 -0500Dec 24, Problems on Congruency of Triangles |Prove Two Triangles are Congruent
https://www.math-only-math.com/problems-on-congruency-of-triangles.html37d86899d03775c1b5a9a7132b36954dHere we will learn how to prove different types of problems on congruency of triangles. 1. PQR and XYZ are two triangles in which PQ = XY and ∠PRQ = 70, ∠PQR = 50°, ∠XYZ = 70°, and ∠YXZ = 60°. Prove that the two triangles are congruent. Solution: In a triangle, the sum ofMon, 24 Dec 2018 15:21:04 -0500Dec 20, Criteria for Congruency | SAS| AAS | SSS | RHS | CPCTC
https://www.math-only-math.com/criteria-for-congruency.html8ac42c8ed16d064fc029ac27becc947eHere we will learn different criteria for congruency of triangles. I. SAS (Side-Angle-Side) Criterion: If two triangles have two sides of one equal to two sides of the other, each to each, and the angles included by those sides are equal then the triangles are congruent.Thu, 20 Dec 2018 16:33:57 -0500Dec 19, Worksheet on Graph of Linear Relations in x, y | Draw the Graph
https://www.math-only-math.com/worksheet-on-graph-of-linear-relations-in-x-y.htmldce9e362d09b852a9cde9acb70c5f43cIn worksheet on graph of linear relations in x, y we will plot different types of equation in the x-y plane. 1. Draw the graph for each of the following: (i) x = 2 (ii) x = -3 (iii) y = 4 (iv) y + 1 = 0 (v) 2x + 3 = 0 2. For each of the following, take three ordered pairWed, 19 Dec 2018 14:43:44 -0500Dec 19, Congruency of Triangles | Definition of Congruent Triangles
https://www.math-only-math.com/congruency-of-triangles.html7d73ac65c2b0db918b29b0854567fc95Two triangles are said to be congruent if they are exactly alike in all respects. If one triangle is placed on the other, the two triangles will coincide exactly with each other, i.e., the vertices of the first triangle will coincide with those of the second. In a pair ofWed, 19 Dec 2018 14:34:26 -0500Dec 16, Worksheet on Slope and Y-intercept | Determine the Slope & Y-intercept
https://www.math-only-math.com/worksheet-on-slope-and-y-intercept.html9fe6a8ed4091b20552977608da1d3ef8In worksheet on slope and y-intercept we will get different types of equations. On understanding slope and y-intercept of graphs of linear relations in x,y. 1. Determine the slope and y-intercept of the line graph for each of the following relations in x, y.Sun, 16 Dec 2018 16:47:19 -0500Dec 13, Worksheet on Plotting Points in the Coordinate Plane |Coordinate Graph
https://www.math-only-math.com/worksheet-on-plotting-points-in-the-coordinate-plane.htmle70b0a7598f390c63e588fe56693e854In worksheet on plotting points in the coordinate plane we will plot different types of co-ordinate points in the x-y plane. 1. Plot the points in the coordinate plane. (i) (6, -2) (ii) (-3, 7) (iii) (2.5, 4.5) (iv) (-5, -3.5)Thu, 13 Dec 2018 16:25:07 -0500Dec 12, Problems on Slope and Y-intercept | Determine the Slope & Y-intercept
https://www.math-only-math.com/problems-on-slope-and-y-intercept.html504c77e98b186c9b748ae603ef2e57bfHere we will learn how to solve different types of problems on slope and y-intercept. 1. (i) Determine the slope and y-intercept of the line 4x + 7y + 5 = 0 Solution: Here, 4x + 7y + 5 = 0 ⟹ 7y = -4x – 5 ⟹ y = -4/7x - 5/7Wed, 12 Dec 2018 17:33:14 -0500Dec 10, Problems on Plotting Points in the x-y Plane | Plot the Points
https://www.math-only-math.com/problems-on-plotting-points-in-the-x-y-plane.html7cc19352c6f9b7bf0714dec3fc39e90dHere we will learn how to solve different types of problems on plotting points in the x-y plane. 1. Plot the points in the same figure. (i) (3, -1), (ii) (-5, 0), (iii) (3, 4.5), (iv) (-1, 6), (v) (-2.5, -1.5) Solution: Draw two mutually perpendicular lines X’OX and Y’OYMon, 10 Dec 2018 16:38:32 -0500Dec 9, Drawing Graph of y = mx + c Using Slope and y-intercept | Examples
https://www.math-only-math.com/drawing-graph-of-y-equals-to-mx-plus-c-using-slope-and-y-intercept.htmled9e2877ad97ba4be793caeacc2e555aHere we will learn how to draw the graph of a linear relation between x and y is a straight line. So, the graph of y = mx + c is a straight line. We know its slope is m and y-intercept is c. By knowing the slope and y-intercept for a line graph, the graph can be easily drawnSun, 9 Dec 2018 17:14:36 -0500Dec 8, Graph of Standard Linear Relations Between x, y | Graph of y = x
https://www.math-only-math.com/graph-of-standard-linear-relations-between-x-y.html9e7274f614942babd53897bba96690adHere we will learn how to draw the graph of standard linear relations between x, y. Graph of x = 0 Some of the orders pairs of values of (x, y) satisfying x = 0 are (0, 1), (0, 2), (0, -1), etc. All the points corresponding to these ordered pairs are on the y-axis becauseSat, 8 Dec 2018 15:35:01 -0500Dec 7, Slope of the Graph of y = mx + c | What is the Graph of y=mx-c?
https://www.math-only-math.com/slope-of-the-graph-of-y-equals-to-mx-plus-c.html83d25d64666293817e26712e43d57f68The graph of y = mx + c is a straight line joining the points (0, c) and -c/m Let M = (-c/m, 0) and N = (0, c) and ∠NMX = θ. Then, tan θ is called the slope of the line which is the graph of y = mx + c. Now, ON = c and OM = c/m. Therefore, in the right-angled ∆MON, tan θ = Fri, 7 Dec 2018 18:02:26 -0500Dec 7, y-intercept of the Graph of y = mx + c | How to Find y-intercept?
https://www.math-only-math.com/y-intercept-of-the-graph-of-y-equals-to-mx-plusc.htmlc00166b8a27297cee644bc7dbafe1d2fIf the graph of y = mx + c cuts the y-axis at P then OP is the y-intercept of the graph, where O is the origin. If OP is in the positive direction of the y-axis, the intercept is positive. But if OP is in the negative direction of the y-axis, the intercept is negative.Fri, 7 Dec 2018 17:56:09 -0500Nov 28, Coordinate Geometry Graph | Graph of Linear Relations Between x, y
https://www.math-only-math.com/coordinate-geometry-graph.html99a8225092cbf975e6b3c0c14600074eHere we will learn how to draw Coordinate geometry Graph. When two variables x, y are related, the value(s) of one variable depends on the value(s) of the other variable. Let x, y be two variables related by 9x - 3y + 4 = 0. Then, y = 3x + \(\frac{4}{3}\).Wed, 28 Nov 2018 17:15:45 -0500Nov 26, Plotting a Point in Cartesian Plane | Determine the Quadrant
https://www.math-only-math.com/plotting-a-point-in-cartesian-plane.html06dd4f1f03ae5596980ff5f58f148c71If the coordinates (x, y) of a point are given, one can plot in the Cartesian x-y plane by taking the following steps. Step I: Observe the signs of the coordinates and determine the quadrant in which the point should be plotted. Step II: Take a rectangular Cartesian frame ofMon, 26 Nov 2018 17:17:29 -0500Nov 25, Quadrants and Convention for Signs of Coordinates | Four Quadrants
https://www.math-only-math.com/quadrants-and-convention-for-signs-of-coordinates.html22c70d5a9851def937ca91828f87795dThe x-axis (XOX’) and y-axis (YOY’) divided the x-y plane in four regions called quadrants. The region of the plane falling in the angle XOY is called the first quadrant. The region of the plane falling in the angle X’OY is called the second quadrant. The region of the planeSun, 25 Nov 2018 16:50:07 -0500