Word Problems on Percentage

Word problems on percentage will help us to solve various types of problems related to percentage. Follow the procedure to solve similar type of percent problems.

Word problems on percentage:

1. In an exam Ashley secured 332 marks. If she secured 83 % makes, find the maximum marks.

Solution:

Let the maximum marks be m.

Ashley’s marks = 83% of m

Ashley secured 332 marks

Therefore, 83% of m = 332

⇒ 83/100 × m = 332

⇒ m = (332 × 100)/83

⇒ m =33200/83

⇒ m = 400

Therefore, Ashley got 332 marks out of 400 marks.


2. An alloy contains 26 % of copper. What quantity of alloy is required to get 260 g of copper?

Solution:

Let the quantity of alloy required = m g

Then 26 % of m =260 g

⇒ 26/100 × m = 260 g

⇒ m = (260 × 100)/26 g

⇒ m = 26000/26 g

⇒ m = 1000 g


3. There are 50 students in a class. If 14% are absent on a particular day, find the number of students present in the class.

Solution:            

Number of students absent on a particular day = 14 % of 50

                                                           i.e., 14/100 × 50 = 7

Therefore, the number of students present = 50 - 7 = 43 students.


4. In a basket of apples, 12% of them are rotten and 66 are in good condition. Find the total number of apples in the basket.

Solution:            

Let the total number of apples in the basket be m

12 % of the apples are rotten, and apples in good condition are 66

Therefore, according to the question,

88% of m = 66

88/100 × m = 66

m = (66 × 100)/88

m = 3 × 25

m = 75

Therefore, total number of apples in the basket is 75.


5. In an examination, 300 students appeared. Out of these students; 28 % got first division, 54 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.

Solution:

The number of students with first division = 28 % of 300 = 28/100 × 300 = 8400/100 = 84

And, the number of students with second division = 54 % of 300

                                                                   = 54/100 × 300

                                                                   =16200/100

                                                                   = 162

Therefore, the number of students who just passed = 300 – (84 + 162) = 54

Fraction into Percentage

Percentage into Fraction

Percentage into Ratio

Ratio into Percentage

Percentage into Decimal

Decimal into Percentage

Percentage of the given Quantity

How much Percentage One Quantity is of Another?

Percentage of a Number

Increase Percentage

Decrease Percentage

Basic Problems on Percentage

Solved Examples on Percentage

Problems on Percentage

Real Life Problems on Percentage

Word Problems on Percentage

Application of Percentage





8th Grade Math Practice

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