When the train passes through a pole or tower or lightpost or tree or a stationary object
If length of train = x meters and speed of the train = y km/hr, then time taken by the train to pass the stationary object = length of the train/speed of the train = x meters/y km/hr.
Note: Change km/hr into m/sec.
Solved examples to calculate when the train passes through a pole or a stationary object.
1. A train 150 m long is running at a uniform speed of 54 km/hr. How much time will it take to cross a pole?
Solution:
Speed of train = 54 km/hr
= 54 × 5/18 m/sec
= 15 m/sec
Length of the train = 150 meters
Therefore, time taken by the train to cross a pole = length of train/speed of train
= 150/15 sec
= 10 sec
Thus, train takes 10 seconds to cross the pole.
2. Find the time taken by a train 300 m long, running at a speed of 54 km/hr in crossing the pole.
Solution:
Length of the train = 300 m
Speed of the train = 54 km/hr
= 54 × 5/18 m/sec
= 15 m/sec
Therefore, time taken by the train to cross the pole = 300 m/15 m/sec
= 20 seconds.
3. A train is running at a speed of 45 km/hr. It crosses a tower in 8 seconds. Find the length of the train.
Solution:
Speed of train = 45 km/hr
= 45 × 5/18 m/sec
= 25/2 m/sec
Time takes to cross the tower = 8 seconds
Length of the train = speed × time
= 25/2 × 8 m
= 100 m
4. A train is running at a speed of 126 km/hr. if it crosses a pole in just 7 second, what is the length of the train?
Solution:
Speed of the train = 126 km/hr
Speed of the train = 126 × 5/18 m/sec = 35 m/sec
Time taken by the train to cross the pole = 7 seconds
Therefore, length of the train = 35 m/sec × 7 sec = 245 m
Relationship between Speed, Distance and Time
Problems on Calculating Distance
Two Objects Move in Same Direction
Two Objects Move in Opposite Direction
Train Passes a Moving Object in the Same Direction
Train Passes a Moving Object in the Opposite Direction
Two Trains Passes in the Same Direction
Two Trains Passes in the Opposite Direction
8th Grade Math Practice
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