Here we will learn multiplying 2digit number by 1digit number. In two different ways we will learn to multiply a twodigit number by a onedigit number.
Examples of multiplying 2digit number by 1digit number:
1. Multiply 20 by 3 by using expanded form
Solution:
20 → 2 tens + 0 ones
× 3 → × 3
6 tens + 0 ones
= 60 + 0
= 60
Therefore, 20 × 3 = 60
2. Multiply 50 by 1 by using short form
Solution:
50 → 50
× 1 → × 1
0 50
(i) First digit of one’s place is multiplied by 1, i.e., 0 × 1 = 0
(ii) Then digit at ten’s place is multiplied by 1, i.e., 5 tens × 1 = 5 tens
Hence, 50 × 1 = 50
3. Multiply 26 by 7 by using expanded form
Solution:
26 → 20 + 6 → 2 tens + 6 ones
× 7 → × 7 → × 7
(2 × 7) tens + (6 × 7) ones
2 tens + 6 ones
× 7 ones
14 tens + 42 ones
= 14 tens + (40 + 2) ones
= 14 tens + 4 tens + 2 ones
= 18 tens + 2 ones
= 180 + 2
= 182
Therefore, 26 × 7 = 182
4. Multiply 48 by 6 by using short form
Solution:
48
× 6
24 ← 48
= 28 tens 8 ones
= 288
Hence, 48 × 6 = 288
(i) 48 × 6 is written in column from.
(ii) 8 ones are multiplied by 6, i.e., 6 × 8 = 48 ones = 4 tens + 8 ones
8 is written is one’s column and 4 tens is gained.
(iii) Gained 4 is carried to the ten’s column.
(iv) Now 4 tens is multiplied by 6, i.e., 4 tens × 6 = 24 tens
(v) Carried 4 tens is added to 24 tens, i.e., 4 tens + 24 tens = 28 tens
5. Find the product of 58 × 5.
Solution:
58
× 5
25 ← 40
= 25 + 4 ← 0
= 29 0
= 290
(i) 8 ones × 5 = 40 = 4 tens + 0 one
(ii) 5 tens × 5 = 25 tens
(iii) 25 tens + 4 tens = 29 tens
Hence, 58 × 5 = 290
6. Multiply 37 by 8
Solution:
3 7
× 8
5 6
+ 2 4 0
2 9 6
(i) 7 ones × 8 = 56 ones = 5 tens 6 ones
56 is placed in such way that 5 comes under tens and 6 under ones
(ii) 3 tens × 8 = 24 tens = 240 ones
= 2 hundreds, 4 tens and 0 ones
240 is placed below 56 in such way that 2 comes under hundreds, 4 under tens and 0 under ones.
Hence, 37 × 8 = 296
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