Now we will learn how to solve direct variations using unitary method.
We know, the two quantities may be linked in such a way that if one increases, other also increases. If one decreases, the other also decreases.
Some situations of direct variations:
● More articles, more money required to purchase.
● More men at work, more work will be done.
● More speed, more distance covered in fixed time.
● More money borrowed, more interest to be paid.
● More working hours, more work will be done.
Solved examples on direct variations using
unitary method:
1. The cost of 3 kg of sugar is $ 60. What will the cost of 8 kg of sugar be?
Solution:
This is a situation of direct variation, now we solve using unitary method.
Cost of 3 kg of sugar = $ 60
Cost of 1 kg of sugar = $ 60/3 = $ 20
Cost of 8 kg of sugar = $ 20 × 8
Therefore, cost of 8 kg of sugar = $ 160
2. If 13 books cost 169, what do 30 books cost?
Solution:
This is a situation of direct variation, now we solve using unitary method.
Cost of 13 books = $ 169.
Cost of 1 book = $ 169/13 = $ 13.
Cost of 30 books = $ 13 × 30.
Therefore, cost of 30 books = $ 390.
3. A labourer gets $ 684 for 9 days. How many days should he work to get $ 912?
Solution:
This is also a situation of direct variation, now we solve using unitary method.
For $ 684, the labourer works 9 days.
For $ 1, the labourer works 9/684 days.
For $ 912, the labourer works 9/684 × 912 days.
Therefore, for $ 912, the labourer works 12 days.
`Situations of Direct Variation
Situations of Inverse Variation
Direct Variations Using Unitary Method
Direct Variations Using Method of Proportion
Inverse Variation Using Unitary Method
Inverse Variation Using Method of Proportion
Problems on Unitary Method using Direct Variation
Problems on Unitary Method Using Inverse Variation
Mixed Problems Using Unitary Method
7th Grade Math Problems
From Direct Variations Using Unitary Method to HOME PAGE
Didn't find what you were looking for? Or want to know more information about Math Only Math. Use this Google Search to find what you need.

New! Comments
Have your say about what you just read! Leave me a comment in the box below. Ask a Question or Answer a Question.