How to find the general solution of an equation of the form cos θ = 1?
Prove that the general solution of cos θ = 1 is given by θ = (2n + 1)π, n ∈ Z.
Solution:
We have,
cos θ = 1
⇒ cos θ = cos π
θ = 2mπ ± π, m ∈ Z, [Since, the general solution of cos θ = cos ∝ is given by θ = 2nπ ± ∝, n ∈ Z.]
⇒ θ = (2m ± 1)π, m ∈ Z, (i.e., n = 0, ± 1,± 2, …………)
⇒ θ = odd multiple of π = (2n + 1)π , where n ∈ Z,(i.e., n = 0, ± 1,± 2, …………)
Hence, the general solution of cos θ = 1 is θ = (2n + 1)π, n ∈ Z (i.e., n = 0, ± 1,± 2, …………)
11 and 12 Grade Math
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