# BODMAS Rules - Involving Integers

We will obey the rules for simplifying an expression using BODMAS rules - involving integers for solving order of operations.

Follow the order of operation as:

1. Bracket  Solve inside the Brackets before Of, Multiply, Divide, Add or Subtract.

For example:

7 × (15 + 5)

= 7 × 20

= 140

2. Of Then, solve Of part (Powers, Roots, etc.,) before Multiply, Divide, Add or Subtract.

For example:

6 + 3 of 7 - 5

= 6 + 3 × 7 - 5

= 6 + 21 - 5

= 27 - 5

= 22

3. Division/Multiplication Then, calculate Multiply or Divide before Add or Subtract start from left to right.

For example:

20 + 21 ÷ 3 × 2

= 20 + 7 × 2

= 20 + 14

= 34

4. Addition/Subtraction At last Add or Subtract start from left to right.

17 + (8 - 5) × 5

= 17 + 3 × 5

= 17 + 15

= 32

Worked-out problems for solving BODMAS rules - involving integers:

Simplify using BODMAS rule:

(a) 25 - 48 ÷ 6 + 12 × 2

Solution:

25 - 48 ÷ 6 + 12 × 2

= 25 - 8 + 12 × 2, (Simplifying ‘division’ 48 ÷ 6 = 8)

= 25 - 8 + 24, (Simplifying ‘multiplication’ 12 × 2 = 24)

= 17 + 24, (Simplifying ‘subtraction’ 25 - 8 = 17)

= 41, (Simplifying ‘addition’ 17 + 24 = 41)

(b) 78 - [5 + 3 of (25 - 2 × 10)]

Solution:

78 - [5 + 3 of (25 - 2 × 10)]

= 78 - [5 + 3 of (25 - 20)], (Simplifying ‘multiplication’ 2 × 10 = 20)

= 78 - [5 + 3 of 5], (Simplifying ‘subtraction’ 25 - 20 = 5)

= 78 - [5 + 3 × 5], (Simplifying ‘of’)

= 78 - [5 + 15], (Simplifying ‘multiplication’ 3 × 5 = 15)

= 78 - 20, (Simplifying ‘addition’ 5 + 15 = 20)

= 58, (Simplifying ‘subtraction’ 78 - 20 = 58)

(c) 52 - 4 of (17 - 12) + 4 × 7

Solution:

52 - 4 of (17 - 12) + 4 × 7

= 52 - 4 of 5 + 4 × 7, (Simplifying ‘parenthesis’ 17 - 12 = 5)

= 52 - 4 × 5 + 4 × 7, (Simplifying ‘of’)

= 52 - 20 + 4 × 7, (Simplifying ‘multiplication’ 4 × 5 = 20)

= 52 - 20 + 28, (Simplifying ‘multiplication’ 4 × 7 = 28)

= 32 + 28, (Simplifying ‘subtraction’ 52 - 20 = 32)

= 60, (Simplifying ‘addition’ 32 + 28 = 60)

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