Application of percentage will help us to apply the procedure to solve reallife percent problems.
Application of percentage:
1. In an election, candidate A got 70 % of the total valid votes. 20 % of the total votes were declared invalid. If the total number of votes is 600000, find the number of valid votes polled in favour of the candidate.
Solution:
Total number of invalid votes = 20 % of 600000
= 20/100 × 600000
= 120000
Total number of valid votes polled = 600000  120000 = 480000
Percentage of valid votes polled in favour of the candidate = 70 %
Therefore Number of valid votes polled in favour of the candidate = 70 % of 480000
= 70/100 × 480000 = 336000 votes
Therefore, the number of valid votes polled in favour of the candidate is 336000.
2. Mother's weight is 25 % more than that of daughter. What percent is daughter's weight less than mother's weight?
Solution:
Let daughter's weight be 100 kg.
Then mother's weight = (100 + 25) kg = 125 kg
If mother's weight is 125 kg, then daughter's weight is 100 kg.
If mother's weight is 1 kg, then daughter's weight is 100/125 kg
If mother's weight is 100 kg, then daughter's weight = (100/125 × 100) kg
Therefore, daughter's weight is 20 % less than that of mother.
3. Kelly requires 36 % to pass. She gets 196 marks and falls short by 20 marks. Find the maximum numbers she could have got.
Solution:
Tanya had scored 20 marks more, she could have scored 36%.
Now, 20 marks more than 196 marks.
Therefore, 196 + 20 = 216
Let maximum marks be x, then 36% of m = 216
⇒ 36/100 × m = 216
⇒ m = 216 × 100/36
⇒ m = 600
Thus, the maximum marks she could have got were 600.
4. In an examination, 460 students appeared. Out of these students; 23 % got first division, 62 % got second division and the remaining just passed. Assuming that no student failed; find the number of students who just passed.
Solution:
Since, the percentage of first division = 23 %
And, the percentage of second division = 62 %
Therefore, percentage of those who just passed = (100 – 23 – 62) %
= (100 – 85) %
= 15 %
Therefore, the percentage of those who just passed = 15 % of 460
= 15/100 × 460
= 6900/100
= 69
Percentage of the given Quantity
How much Percentage One Quantity is of Another?
Real Life Problems on Percentage
8th Grade Math Practice
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