When we add two or more numbers, we add digits of one’s place, ten’s place etc. If the sum of digits of one’s place is more than 9, it contains the number having tens and ones, as 8 + 5 = 13 = 10 + 3, i.e., one ten and 3 ones. This one ten is carried over to the digit or digits in the ten’s place.
Solved examples 2digit addition with carryover are given in the following:
1. Add 59 and 37.
Solution:
Tens Ones 15 9 + 3 7 9 6 Therefore, sum of 59 and 37 = 96 
(i) Digits at one’s place are added first i.e. 9 + 7 = 16 = 1 ten and 6 ones (ii) 1 (one) ten is carried over to ten’s side.
(iii) Now digits at tens place are added i.e., 5 + 3 = 8 tens. To this sum i.e., 8, the carried over 1 ten is also added. Thus, 8 tens + 1 ten = 9 tens. (iv) Therefore, sum is 9 tens and 6 ones, i.e., 96. 
2. Add 65 and 47.
Solution:
Tens Ones 16 5 + 4 7 11 2 Therefore, sum of 65 and 47 = 112 
(i) Digits at one’s place are added first i.e. 5 + 7 = 12 = 1 ten and 2 ones (ii) 1 (one) ten is carried over to ten’s side. (iii) Now digits at tens place are added i.e., 6 + 4 = 10 tens.
To this sum i.e., 10, the carried over 1 ten is also added. Thus, 10 tens + 1 ten = 11 tens. (iv) Therefore, sum is 11 tens and 2 ones, i.e., 112. 
Or
6 5 = 6 tens + 5 ones + 4 7 = 4 tens + 7 ones = 10 tens + 12 ones = 10 tens + 1 ten + 2 ones = 11 tens + 2 ones = 112 
5 ones + 7 ones = 12 ones = 1 ten + 2 ones
6 tens + 4 tens = 10 tens 10 tens + 1 ten (carried over) = 11 tens The sum = 11 tens + 2 ones = 112 
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